This isn't good- I don't get a lot of the hw questions (Are there step by step answers for the sets?). In any case, let me point out a few that I have trouble on.
Set 1
18. I looked for A', which is .5(bh'+hb') and got .5(-20(.5)-15(1/3))
30. The answer is e but e doesn't satisfy the first requirement
Set 2
4. I don't get which formula I should use
15. After cross multiplying, I got y=2x
19 I have no idea how the nswer is a, besides the fact that there is an asymptote at y=10
31. Which formula did you use?
33. You l'hopital, I differentiated it to -8sin4x and -32cos4x and neither solution matches the answer
39. Don't quite get how they shaped the formula.
40. I differentiated it and got zero
Set 3
4. Which formula did you use?
7. Isn't is 3/4
9. I got -1/720
Thanks
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2008
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April
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- Limit of a series
- Set #1
- #20 from Multiple Choice Set#1 - No calculators
- #20
- #4, Error Problems
- Finding IOC
- Infinite Series Homework Help
- This is for Mrs. Carlson:When using p-series or ha...
- Infinite Series
- #4c from HW #21
- HW 21
- #18 from HW #19
- Particle motion
- quiz on friday
- Need help
- HW#19 & #20
- #6b from HW #17
- Number 10 from Set #3
- Set 1
- Number 30 from Set#2
- Finding growth rate
- MC sets
- MC set#1 answers
- MC Set #1
- HW #15: 18c
- Hw #12+
- Test on Friday
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April
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4 comments:
For 18, you did the right thing. it should come out to be -5 - 5/2 which equals -15/2 which equals -7.5 (d).
For 30, a number of people got the answer to be (c), but no one is sure how the answer is (e).
Set 2
#4, you use the formula for average value : integral from a to b f(x)dx
#15, I'm not sure what you did here but you start out with the expression integral ydy = integral 4xdx. Then after solving and plugging in y(0)=1 to find the C value, you should get (e) to be the answer.
#19, you have to look at the way the lines face. If it goes like / then it's positive and \ is negative. What I did was plug in values for y to determine the correct slope field. (Notice when y=10, dy/dt is 0)
#31, I used the separation by parts. I set u=9x, dv= cos(3x +1) and you go from there.
#33 Did you get lim as x->0, (4cos4x)/(2x + 8) after the first l'hopital? I got that and it seems to work from there.
#39, I don't quite get what you're asking.
#40, I need help here too!
Thanks for helping, how could I have been so absent-minded?
But how do you anti-differentiate set 2/#4? My answer, by u-subsitution, was -8pi. I don't get how the ln got there.
I got Set 2/#39, but #40 and set 3 is still confusing :(
Oh!For set 2 #4, it's the rule for integrating the a^x not differentiating. You're probably thinking of the wrong one. And for 40, you have to multiply by the conjugate and the x^2 cancel out. Then, you change the remaining x to square root of x^2 cause that's the same thing. Then , you combine the root until you get 1+square root of (1+1/x). (1+1/x) is e^1. so when you ln you get .5. Hopefully, its not too confusing.
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