I know the hw packet is due tomorrow, but I just want to know how you find out that P is a local maximum. I looked at the solutions, but I still don't get it!
Have a great spring break everybody!
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2 comments:
at P (3,2) y'=0 so it's a max or min. then you find that y"=-2/7<0 so graph is concave down. that means curve has a local max at P
oh, that makes sense! thanks!
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