#12
1d. I get how P'(o) =2, but why is t=5?
2a. How did it arrive at y=.5?
4a. What formula was used to find out the limit? Is it the sae used for 2a in #13?
4b.The answer states it occurs when the population is half of the carrying cpacity- how do you know that?
#13
2c. The range is just when f(x) is positive. Is f(x), then, only a function when it's positive? The same thing happens with 5b.
#14
1b. Strangely, when I do it, it's -(2+sinx)sinx-(cosx)^2=0, yet the answers say it's at sinx=.5. What am I missing?
9b. I don't get how they found the x and y intercepts.
Thanks for your help!
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4 comments:
For HW 14, 1b, if you distribute, you will have a -sin^2 and -cos^2 in the expression, and they equal "-1"
for HW #12 1d this is what i did:
P'(0) = 1-3 = -2
p(0) = 50
so i made an equation for the tangelt line which was y=-2x+50 and i set that less than or equal to 40 and found that x has to be greater than or equal to 5 and i just substituted my x with a t
and for HW #14 9b -
how come you are looking for the x and y intercepts? it only asks for the value of w that would make A(w) a minimum and you can solve that by looking at the first derivative and of A(w)
**first derivative of A(w)
HW #13, 2c. I'm pretty sure range means through what y-values does f(x) pass. So when you look at the graph, you see that it's minimum is at -1/e and the maximum is infinity.
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