CHS Calc BC: HW 21

Monday, April 21, 2008

Does anyone know how to do 2c?
Thanks

MariaCJen said...: Here's what I did (but I'm not sure if it's right) -

I used that ln |3/2| = ln |(5/2)-1|

and

ln |(5/2)-1| = (1/2) - (1/2)(1/2)^2 +(1/3)(1/2)^3 + ... from the series i found in part b

and i simplified and i got

(1/2) - (1/8) + (1/24) + ..

and i found which fraction is less than 0.05 which is 1/24 and i just found the value of the series until (1/24) so that would be (1/2) - (1/8) which equals 3/8 which is what the answer sheet says... so i'm guessing that's how they did it? I'm not exactly sure about how to do it but this is just a guess based from what I saw; April 21, 2008 at 9:17 PM
Anonymous said...: I think you're supposed to use the Remainder Estimation Theory, but I can't really remember how to do it, even with looking at the notes. Sorry about that.; April 21, 2008 at 9:18 PM
Anonymous said...: Oh, that sounds good, Maria. It makes sense. So yeah, scratch what I said then.; April 21, 2008 at 9:19 PM
Cristina said...: How come x=1/2?; April 22, 2008 at 10:19 PM