Sunday, December 30, 2007

I need help!!!!

Did anyone do the suspect problem for Set#19. I did it a couple times but I can't get an answer that makes sense. Can someone help me?

5 comments:

Daryl Wang said...

I just set the right-hand limit, left-hand limit, and function value equal to one another and the left and right hand derivatives equal to another. I'm not sure if this is technically correct, but I substituted one into the derivative equation and got 2a=b. Then I substituted 2a for b and one for x into the equation with the limits and function value. I got a clean integer value when I added a and b that I haven't used since, so I think it's right, but it could be wrong.

Anonymous said...

did you get 10?

judy said...

i got 11 for this question.

Anonymous said...

how?

MariaCJen said...

here's what i did in order:
1) i plugged 1 into the two equations in place of x and then i set the two equations equal to each other
2) then i took the derivative of the two original equations (the one's with x's in it) and i set the two derivatives equal to each other
3) then, using the equation i found 1) and 2), i found the value of a and b and added the two variables together

sorry if it's confusing!

do you still need help with this? if you do, you can ask me at Elite tomorrow if you want during break even though it's like only 5 minutes haha i'll try to explain it if you want