A few questions that I've been absolutely stumped on:
#3a. Let R be the region of the graph of y=lnx and x=3 and the x-axis. When finding the region of R, I differentiated y=lnx from x=0 to 3. My answer was 3ln3-3, but it should be 3ln3-2. Did anyone else get this answer?
b and c. I am also confused as to how the volumes were set up.
#4c. Why is it, when you use disks, the endpoints of the differentiable equations are different?
c. I got k=4 when the answer is k=.995. I divided the answer in 6b in half, differentiated the function, and then put k in the place of x. Then I graphed it to see when the differentiated function matched y=one half of 6b. What am I doing wrong?
#7. What do they mean by the chords A(-4,0) and B(0,2)? How do you figure out if it is tangent to y^2=8-x^(3/2)?
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3 comments:
for 3a you are supposed to integrate from 1 to 3
4c i used shells and i think it's easier this way
for 6c i got .995
maybe u plugged the numbers wrong?
#7 i'm not sure but this is what i did...
cord AB means a line?
so use the pts to find slope
and then find derivative of
y^2=8-x^(3/2)
and set them equal to each other
so it's 1/(2y)=1/2
so y=1
and plug back to equation and get x=-3
sorry if this is wrong
actually the process is correct for #7, but you wrote the wrong equation. you're supposed to find the derivative of y^2=4+x, then you'll get 1/(2y)=1/2.
the equation you wrote was from number 6
Thanks
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