Friday, January 4, 2008

AB Clue Problem Set # 26

Hi! I need help on Set # 26 (Location). I integrate V(t) and it came out something like this: V’(t) = (1/3)t^3 - (39-6)t^2 + 40t + 4 Is that correct? And then… I got stuck.

3 comments:

judy said...

i think what you do is take another derivative because
you are looking for where CHANGE of velocity is decreasing.

judy said...

oh and then you set it equal to zero and do the number line.
part where it is negative is the decreasing portion. and so on. (:

MariaCJen said...

I looked at the 2nd derivative because it's asking for the change in velocity which would be the acceleration. I set the 2nd derivative equal to zero and found a and b and plugged it into 3a-b.