June 3rd.
Apparently I have a "disc bulging disease in my L5-S1". But I'll be okay. I have an appointment with Physical Therapy scheduled already, and will figure out how to deal with it. Thankfully it's not MS or something worse.
I'm looking forward to coming back. =)
Mrs. Carlson
Friday, May 23, 2008
Wednesday, May 7, 2008
Sooo...how was it??
I was thinking about all of you this morning...wondering at what part of the test you were on during various times...
Did you feel prepared for the FRQs? Did they have anything on there this year that seemed different from the years past? I can't wait to hear from you guys!
Did you feel prepared for the FRQs? Did they have anything on there this year that seemed different from the years past? I can't wait to hear from you guys!
Tuesday, May 6, 2008
Good luck tomorrow morning and I'll be thinking of all of you!
I won't be there tomorrow as I had thought; I'm now awaiting an appointment with Neurology. So I'll be gone at least 2 more weeks. But don't worry about me.
You are prepared, for the most part. Just go over the Formulas & Theorems packet for any last minute items you might want to review.
I wish I could be there for you!
Tell me all about it later, okay?!
-Mrs. Carlson
You are prepared, for the most part. Just go over the Formulas & Theorems packet for any last minute items you might want to review.
I wish I could be there for you!
Tell me all about it later, okay?!
-Mrs. Carlson
Monday, May 5, 2008
I hope it helped...
for those of you that showed up, I hope it was helpful. It was nice to be there. Makes it easier for me to go back to work. =) Of course I'll be sad having to leave the new baby, but I'm comfortable in the classroom, if that makes any sense.
Please continue to post questions!
I *still* haven't yet heard back from the doctor. I had called again on my way to the review. Soooo, right now I am assuming that I will be back there on Wednesday. If so, I will be in my room around 7:15ish for support and last minute pep-talks.
A couple of things to do beforehand:
-make sure your calculator has fresh, new batteries. or bring some with you.
-set your calculator to RADIAN mode
-NO scientific calculators allowed; so leave them. you are allowed up to TWO graphing calculators (no QWERTY keypads allowed; so TI-89s are OK).
-breathe. you'll be fine.
Get a good night's rest and eat breakfast. don't load up on sugar. eat something healthy.
See you there!
Mrs. Carlson
Please continue to post questions!
I *still* haven't yet heard back from the doctor. I had called again on my way to the review. Soooo, right now I am assuming that I will be back there on Wednesday. If so, I will be in my room around 7:15ish for support and last minute pep-talks.
A couple of things to do beforehand:
-make sure your calculator has fresh, new batteries. or bring some with you.
-set your calculator to RADIAN mode
-NO scientific calculators allowed; so leave them. you are allowed up to TWO graphing calculators (no QWERTY keypads allowed; so TI-89s are OK).
-breathe. you'll be fine.
Get a good night's rest and eat breakfast. don't load up on sugar. eat something healthy.
See you there!
Mrs. Carlson
Sunday, May 4, 2008
Here's what we'll do:
Tomorrow, Monday, at 5pm in my room for 2 hours. I will double check with Mr. Wentz to make sure the time is ok to be on campus. If not, I will let you guys know. I'm sorry it can't be sooner or longer. I'll actually have to have Brennan (the littlest one) with me (can't get around this).
I can't come on Tuesday because my son has a baseball game Tuesday.
I will *hopefully* also know sometime tomorrow what day I will be returning. Again, I will let you all know.
So, please spread the word about tomorrow.
Thanks!
I can't come on Tuesday because my son has a baseball game Tuesday.
I will *hopefully* also know sometime tomorrow what day I will be returning. Again, I will let you all know.
So, please spread the word about tomorrow.
Thanks!
#22 and 23 from MC Set #2
For #22, how does the answer come out to be e? I keep 2+e, which is the answer for choice C. Does anyone know how to do this?
For #23, I don't understand this problem either. Any help would be greatly appreciated..
Thanks.
For #23, I don't understand this problem either. Any help would be greatly appreciated..
Thanks.
#14 from MC Set#2
I keep getting 120 lbs. Is it supposed to be 120 lbs or 60 lbs. Does anyone know how to solve it so that the answer is D (60 lbs.)? Thanks.
Saturday, May 3, 2008
How about...
if our campus can't accommodate us after 6, how about at the library? In one of their conference rooms? Does it need to be reserved? Can that be done ahead of time? Does anyone know?
Thursday, May 1, 2008
Q&A Session
Hannah emailed me to ask me if there's a possibility of having a Q&A session Monday or Tuesday to clear up questions. What's the time that would work for most of you that would be interested? Monday like at 4pm? Tuesday?
I am set to return Wednesday (story about all that on my blog later) and your exam is in the morning, so those two days would seem to be the best candidates. I'll still need to double-check with my husband to make sure that he can watch the kids, but I'd anticipate that I can be there for about 2 hours.
Please post your suggestions as comments.
I am set to return Wednesday (story about all that on my blog later) and your exam is in the morning, so those two days would seem to be the best candidates. I'll still need to double-check with my husband to make sure that he can watch the kids, but I'd anticipate that I can be there for about 2 hours.
Please post your suggestions as comments.
MS #2
9. I got 3x^2(x)^(x^2)(lnx)
12. I moved the dy and dx onto opposite sides and ended up with (1/(x^2-x^3+1))^.5
14. The formula I used was the antiderivative of (10/4)x from 10 to 14, which is 110.
15. I don't see how e^(-x) converges, since, as the particle approaches infinity, I got 1, which by nth term would mean it diverges.
20. This is confusing since, by the information given, you can deduct two different answers for radius
22. Since the numerator is an additional equation, maybe the n! crosses out the numerator, but I don't see how the relationship of the function with e.
23. Integrating it, the function looks like sinx-x+(x^3/3) from pi to zero, which does not equal to pi.
29. Looks like the derivative of cos(x+h), but where did the 2 in -sinx come from?
33. When setting the ln function to infinity, I gor pi/1/1/x, which when appraoching infinity, should equal to zero, which would make the answer (a). Did anyone else get that?
36. My answer slightly differed, with 3x^2(x^2+2)^(1/2). Did anyone else get that?
44. The answer makes it so that x(t), not a(t), tells the time when the v(t) is increasing, but why?
Lastly,
45. If n is approaching infinity, then wouldn't the answer be a)0, since (1/n) approaching infinity is zero and sin(0)=0?
12. I moved the dy and dx onto opposite sides and ended up with (1/(x^2-x^3+1))^.5
14. The formula I used was the antiderivative of (10/4)x from 10 to 14, which is 110.
15. I don't see how e^(-x) converges, since, as the particle approaches infinity, I got 1, which by nth term would mean it diverges.
20. This is confusing since, by the information given, you can deduct two different answers for radius
22. Since the numerator is an additional equation, maybe the n! crosses out the numerator, but I don't see how the relationship of the function with e.
23. Integrating it, the function looks like sinx-x+(x^3/3) from pi to zero, which does not equal to pi.
29. Looks like the derivative of cos(x+h), but where did the 2 in -sinx come from?
33. When setting the ln function to infinity, I gor pi/1/1/x, which when appraoching infinity, should equal to zero, which would make the answer (a). Did anyone else get that?
36. My answer slightly differed, with 3x^2(x^2+2)^(1/2). Did anyone else get that?
44. The answer makes it so that x(t), not a(t), tells the time when the v(t) is increasing, but why?
Lastly,
45. If n is approaching infinity, then wouldn't the answer be a)0, since (1/n) approaching infinity is zero and sin(0)=0?
Wednesday, April 30, 2008
Limit of a series
Does anyone know how to do problems like set 1 #43? I don't remember learning anything about finding the limit of an infinite series. Anyone know what to do?
Monday, April 28, 2008
Set #1
Let's get straight to the questions.
5. I'm not able to come to a conclusion from the info given
21. Do you differentiate the unction and if so, what comes next?
23. I got (1/h) [ (-e^(-1)/2+(1/2e)]
28. The functions looks more like a parabola than a sphere- I'm not sure how they arrived at a volume here.
30. I anti-differentiated it to (e^(1+lnx))/(1/x) and then came to 16e-4e=12e.
35. I differentiated [(1/2)y(3^.5/2)y] and got 36(3)^.5
36. I differentiated x^2-kx from 2k to zero and got k^3=54.
37.For f'(g(0)), I got 11, so it already isn't working out for me.
38. Using the arc formula, I came to [(35-4x^2)/(36-4x^2)]^.5, which I should differentiate from three to zero, although the answer seems unlikely.
43. I don't see the connection between the antiderivative of x^2 and the limit above
45. We're not allowed to use calculator, so I'm further perplexed as to what they're trying to find.
Thanks for your help.
5. I'm not able to come to a conclusion from the info given
21. Do you differentiate the unction and if so, what comes next?
23. I got (1/h) [ (-e^(-1)/2+(1/2e)]
28. The functions looks more like a parabola than a sphere- I'm not sure how they arrived at a volume here.
30. I anti-differentiated it to (e^(1+lnx))/(1/x) and then came to 16e-4e=12e.
35. I differentiated [(1/2)y(3^.5/2)y] and got 36(3)^.5
36. I differentiated x^2-kx from 2k to zero and got k^3=54.
37.For f'(g(0)), I got 11, so it already isn't working out for me.
38. Using the arc formula, I came to [(35-4x^2)/(36-4x^2)]^.5, which I should differentiate from three to zero, although the answer seems unlikely.
43. I don't see the connection between the antiderivative of x^2 and the limit above
45. We're not allowed to use calculator, so I'm further perplexed as to what they're trying to find.
Thanks for your help.
#20 from Multiple Choice Set#1 - No calculators
Does anyone know how to explain this? I tried plotting points, but my graph doesn't come out as the same one that they give us.. what am I doing incorrectly?
Thursday, April 24, 2008
#20
For part A...
How come the third term is (1/16) when even the solutions say 2!/4(4) ?
For part B...
Where does the (x-5) in the Ratio Test come from?
How come the third term is (1/16) when even the solutions say 2!/4(4) ?
For part B...
Where does the (x-5) in the Ratio Test come from?
#4, Error Problems
I'm stuck on 4. I can't find what the general form of the derivative is, and I can't set up the general term of the power series, so I can't continue on with the problem. Also, does anyone how to solve the error problems like 4c. The solutions mentioned the alternating series test, but I don't think we ever learned how to estimate error with alternate series. Anyone know what to do?
Wednesday, April 23, 2008
Finding IOC
Hi guys! Is anyone here good at finding the IOC? I have difficult time with this subject so can someone please help me? For example: Infinites Series number 4. How would you know that the IOC is -0.6_< x _< 0.6? I am confuse.
Tuesday, April 22, 2008
Infinite Series Homework Help
Infinite Series is really difficult for me to understand...
Anyways I need help on #2-c and #4-c...
I know for number #4-c you use the Remainder Theorem but can someone help me understand how to use that please.
Thanks
Anyways I need help on #2-c and #4-c...
I know for number #4-c you use the Remainder Theorem but can someone help me understand how to use that please.
Thanks
This is for Mrs. Carlson:
When using p-series or harmonic series, do you have to equate it to DCT or LCT or can you just write the similiar equation and the formula?
For instance, woudl 1/n, diverges, harmonic series, be acceptable or do we have to equate the similiar equation to the orignial equation through DCT or LCT?
Onto the HW:
6b. The answer integrated it and as the limit approached infinity, it was heading towards infinity. Why, then does it diverge? It's not using the nth term test, is it?
9b. Since f''(x) is less than zero, does this mean that there is a relative max as x=2?
13c. I don't get the significance of the integral's limits being at x=z and x=0. There doesn't seem to be any difference.
14a. When testing endpoints at x=-1 and x=1, the resuult tends to be the same. So why the function diverges at x=-1 and vice versa at x=1 leaves me puzzled.
15b. a= -3(1/4) and it looks like r=1/4. But the answer would equal to -1 then and that wouldn't make sense.
When using p-series or harmonic series, do you have to equate it to DCT or LCT or can you just write the similiar equation and the formula?
For instance, woudl 1/n, diverges, harmonic series, be acceptable or do we have to equate the similiar equation to the orignial equation through DCT or LCT?
Onto the HW:
6b. The answer integrated it and as the limit approached infinity, it was heading towards infinity. Why, then does it diverge? It's not using the nth term test, is it?
9b. Since f''(x) is less than zero, does this mean that there is a relative max as x=2?
13c. I don't get the significance of the integral's limits being at x=z and x=0. There doesn't seem to be any difference.
14a. When testing endpoints at x=-1 and x=1, the resuult tends to be the same. So why the function diverges at x=-1 and vice versa at x=1 leaves me puzzled.
15b. a= -3(1/4) and it looks like r=1/4. But the answer would equal to -1 then and that wouldn't make sense.
Monday, April 21, 2008
Infinite Series
Wow, what a confusing chapter
2b. The answer antidifferentiated it and added a "c." When integrating a series, do you always have to add a c? Also, I don't get how they got c to equal to -2, I mwan, I know they put ln(2-1)=0, but I don't understand why they did that.
4a. When you find f'(0) and f''(0)...I got -4xe^(-2x^2), 16xe^(2e^9-2x^2), so when you plug in the zero, f'(0)=0 and f''(o)=0, so apparently, the answer is just f(0) , since the other functions=0. What am I doing wrong?
b How do I know IOC if I don't have an r?
c.The answer put it at lf(x)-g(x)l is less than or greater than (16x^8)/4!. How did they know to stop at the 4th degree?
7a. I don't get how they found the equation to use to for finding the IOC.
9d. The LaGrange formula confuses me because I don't know to which degree I should use. In this case, they use it to the 4th degree.
10b. The LaGrange formula confuses me because I don't know to which degree I should use. Why is it the 4th degree in this case?
If you don't get what I'm asking, could you just show me what ways you used to solve the problem or what I may be doing incorrectly? Thanks.
2b. The answer antidifferentiated it and added a "c." When integrating a series, do you always have to add a c? Also, I don't get how they got c to equal to -2, I mwan, I know they put ln(2-1)=0, but I don't understand why they did that.
4a. When you find f'(0) and f''(0)...I got -4xe^(-2x^2), 16xe^(2e^9-2x^2), so when you plug in the zero, f'(0)=0 and f''(o)=0, so apparently, the answer is just f(0) , since the other functions=0. What am I doing wrong?
b How do I know IOC if I don't have an r?
c.The answer put it at lf(x)-g(x)l is less than or greater than (16x^8)/4!. How did they know to stop at the 4th degree?
7a. I don't get how they found the equation to use to for finding the IOC.
9d. The LaGrange formula confuses me because I don't know to which degree I should use. In this case, they use it to the 4th degree.
10b. The LaGrange formula confuses me because I don't know to which degree I should use. Why is it the 4th degree in this case?
If you don't get what I'm asking, could you just show me what ways you used to solve the problem or what I may be doing incorrectly? Thanks.
Subscribe to:
Posts (Atom)